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MathsMaths192 views·Updated Jun 26, 2026·11 pages

AS Level Maths: Key Concepts in Chapters 1, 2, and 3

user profile picture
jayne@k.jayn3

Algebra and quadratics form the backbone of A-level maths, connecting...

1
of 10
Algebra
and
Quadratics Rationalising Denominators

Solving Quadratic Equations

Quadratic Simultaneous Equations

Linear Simultaneous Equati

Algebra and Quadratics Overview

You're about to dive into one of the most powerful areas of maths that'll serve you well beyond your A-levels. Quadratics appear everywhere - from calculating projectile paths to optimising business profits.

This topic brings together loads of interconnected skills that build on each other. Master the basics like expanding brackets and factorising, then you'll find the advanced stuff like discriminants and modelling much easier to tackle.

Key insight: Think of quadratics as a toolkit - each method (factorising, completing the square, quadratic formula) is just a different tool for the same job.

The beauty of this topic is that once you understand the patterns, you'll spot them everywhere in maths and science.

2
of 10
Algebra
and
Quadratics Rationalising Denominators

Solving Quadratic Equations

Quadratic Simultaneous Equations

Linear Simultaneous Equati

Topic Mind Map

Your quadratic journey covers these essential skills that all connect together brilliantly. Index laws and surds give you the foundation, whilst expanding brackets and factorising are your go-to techniques for simplifying expressions.

The real power comes with solving quadratic equations using methods like completing the square and the quadratic formula. You'll also explore how the discriminant tells you exactly how many solutions to expect.

Functions and quadratic graphs help you visualise what's happening, while simultaneous equations (both linear and quadratic) show how different relationships interact. Quadratic inequalities and graphic inequalities extend this to ranges of values.

Study tip: Don't try to learn these topics in isolation - they're all connected and understanding one makes the others much clearer.

Finally, modelling with quadratics shows you how all this theory applies to real-world problems, making your maths genuinely useful.

3
of 10
Algebra
and
Quadratics Rationalising Denominators

Solving Quadratic Equations

Quadratic Simultaneous Equations

Linear Simultaneous Equati

Completing the Square

Completing the square transforms messy quadratics into a much cleaner form that's easier to work with. Think of it as reorganising your bedroom - same stuff, but now you can actually find things!

The basic pattern is turning ax2+bx+cax^2 + bx + c into (x+b2)2+constant(x + \frac{b}{2})^2 + \text{constant}. For 2x2+6x+72x^2 + 6x + 7, you get (x+3)2+9(x + 3)^2 + 9. The key is halving the coefficient of xx, then adjusting the constant.

When the coefficient of x2x^2 isn't 1, just factor it out first. For 2x2+2x+22x^2 + 2x + 2, factor out the 2 to get 2(x2+x+1)2(x^2 + x + 1), then complete the square inside the brackets.

Exam tip: Completing the square is brilliant for finding turning points of parabolas and solving quadratics that don't factorise neatly.

This technique is your secret weapon for tricky exam questions - once you've got the completed square form, finding vertices, roots, and ranges becomes straightforward.

4
of 10
Algebra
and
Quadratics Rationalising Denominators

Solving Quadratic Equations

Quadratic Simultaneous Equations

Linear Simultaneous Equati

Functions and Finding Roots

A function is just a mathematical machine that takes an input and gives you exactly one output. The notation f(x)f(x) simply means "function of xx" - nothing scary about it!

The domain is your set of possible inputs, whilst the range is all the possible outputs. Think of a vending machine: you can only put in certain coins (domain), and you only get specific snacks out (range).

Finding roots means solving f(x)=0f(x) = 0 - basically asking "when does this function hit the x-axis?". You can use completing the square or the quadratic formula for this. For f(x)=x2+6x+5f(x) = x^2 + 6x + 5, factorising gives you (x+1)(x+5)=0(x+1)(x+5) = 0, so x=1x = -1 or x=5x = -5.

Quick check: Always verify your roots by substituting back into the original equation.

Functions are everywhere in real life - from calculating your phone bill to predicting population growth. Master the basics here and you'll breeze through more advanced topics later.

5
of 10
Algebra
and
Quadratics Rationalising Denominators

Solving Quadratic Equations

Quadratic Simultaneous Equations

Linear Simultaneous Equati

Surds and Rationalising Denominators

Surds are just square roots that don't work out to nice whole numbers. So 9=3\sqrt{9} = 3 (not a surd), but 7\sqrt{7} stays as 7\sqrt{7} because there's no simpler form.

The key surd rules are: a×b=ab\sqrt{a} \times \sqrt{b} = \sqrt{ab} and ab=ab\frac{\sqrt{a}}{\sqrt{b}} = \sqrt{\frac{a}{b}}. To simplify surds, look for square factors: 8=4×2=22\sqrt{8} = \sqrt{4 \times 2} = 2\sqrt{2}.

Rationalising denominators means getting rid of surds from the bottom of fractions. When you've got something like 5abc\frac{5}{a\sqrt{b} - c}, multiply top and bottom by the conjugate (ab+c)(a\sqrt{b} + c) to eliminate the surd.

Memory trick: Think of rationalising as "making the denominator rational" - no square roots allowed on the bottom!

This might seem purely theoretical, but surds pop up constantly in trigonometry, calculus, and physics. Getting comfortable with them now saves you loads of time later.

6
of 10
Algebra
and
Quadratics Rationalising Denominators

Solving Quadratic Equations

Quadratic Simultaneous Equations

Linear Simultaneous Equati

The Quadratic Formula

The quadratic formula x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} is your reliable backup when factorising gets messy. It works for any quadratic equation in the form ax2+bx+c=0ax^2 + bx + c = 0.

For x2+5x+3=0x^2 + 5x + 3 = 0, you've got a=1a = 1, b=5b = 5, c=3c = 3. Plugging these in gives x=5±132x = \frac{-5 \pm \sqrt{13}}{2}. The ±\pm means you get two solutions (or sometimes one repeated solution).

With 3x22x4=03x^2 - 2x - 4 = 0, be careful with signs: a=3a = 3, b=2b = -2, c=4c = -4. This gives x=2±526=1±133x = \frac{2 \pm \sqrt{52}}{6} = \frac{1 \pm \sqrt{13}}{3} after simplifying.

Formula tip: Always double-check your aa, bb, and cc values - getting these wrong is the most common mistake.

The quadratic formula never lets you down, even when the numbers get ugly. It's particularly useful for non-calculator questions where exact answers with surds are expected.

7
of 10
Algebra
and
Quadratics Rationalising Denominators

Solving Quadratic Equations

Quadratic Simultaneous Equations

Linear Simultaneous Equati

The Discriminant

The discriminant is the bit under the square root in the quadratic formula: b24acb^2 - 4ac. It's like a crystal ball that tells you exactly how many solutions your quadratic has before you even solve it!

When b24ac>0b^2 - 4ac > 0, you get two distinct roots - your parabola crosses the x-axis twice. When b24ac=0b^2 - 4ac = 0, there's one repeated root - the parabola just touches the x-axis at one point.

If b24ac<0b^2 - 4ac < 0, you get no real roots - your parabola doesn't touch the x-axis at all. This is incredibly useful for sketching graphs and understanding the behaviour of quadratic functions.

Graph connection: The discriminant tells you about x-intercepts without having to draw the whole graph.

This concept becomes crucial when you're analysing quadratic inequalities or determining how many times a line intersects a curve. It's one of those tools that seems simple but proves incredibly powerful.

8
of 10
Algebra
and
Quadratics Rationalising Denominators

Solving Quadratic Equations

Quadratic Simultaneous Equations

Linear Simultaneous Equati

Modelling With Quadratics

Real-world applications of quadratics are everywhere, and projectile motion is a classic example. The equation h(t)=12.25+14.7t4.9t2h(t) = 12.25 + 14.7t - 4.9t^2 models an object's height over time.

The constant term (12.25) represents the initial height when t=0t = 0. The coefficient of t2t^2 is negative because gravity pulls objects downward, creating the characteristic parabolic path.

To find when the object hits the ground, set h(t)=0h(t) = 0 and solve. Using completing the square or the quadratic formula, you get t=3.68t = 3.68 seconds (ignoring the negative solution since time can't be negative).

Real-world tip: Always consider whether your mathematical solutions make physical sense in the context.

Quadratic modelling appears in business (profit optimisation), engineering (structural design), and countless other fields. Understanding how to interpret the coefficients and solve these problems gives you powerful analytical skills.

9
of 10
Algebra
and
Quadratics Rationalising Denominators

Solving Quadratic Equations

Quadratic Simultaneous Equations

Linear Simultaneous Equati

Simultaneous Equations

Simultaneous equations are like mathematical puzzles where you find values that satisfy multiple conditions at once. You might get one solution, two solutions, no solutions, or even infinite solutions depending on how the equations relate.

Elimination works by adding or subtracting equations to eliminate variables. For 3x+y=83x + y = 8 and 6x3y=96x - 3y = 9, multiply the first by 3 to get matching yy terms, then add to eliminate yy completely.

Substitution involves solving one equation for a variable, then plugging that into the other equation. It's particularly useful when you've got quadratic simultaneous equations where one equation has squared terms.

Strategy choice: Use elimination for linear systems, substitution when you've got quadratics or when one equation is already solved for a variable.

Graphically, solutions are intersection points. Linear equations give straight lines, whilst quadratic equations give curves. Where they cross represents your solution coordinates.

10
of 10
Algebra
and
Quadratics Rationalising Denominators

Solving Quadratic Equations

Quadratic Simultaneous Equations

Linear Simultaneous Equati

Quadratic Simultaneous Equations

When you mix quadratic and linear equations, things get more interesting - you can get up to two intersection points. Start by substituting the linear equation into the quadratic one.

For x2+y=3x^2 + y = 3 and y=x23x+1y = x^2 - 3x + 1, substitute to get x2+(x23x+1)=3x^2 + (x^2 - 3x + 1) = 3, which simplifies to x2x2=0x^2 - x - 2 = 0. Factorising gives (x+1)(x2)=0(x+1)(x-2) = 0, so x=1x = -1 or x=2x = 2.

The discriminant predicts how many solutions you'll get before solving. After substitution and simplification, calculate b24acb^2 - 4ac for your resulting quadratic. Positive means two intersections, zero means one (tangent), negative means none.

Discriminant power: Use b24acb^2 - 4ac to check your work - if you found two solutions but the discriminant is negative, you've made an error somewhere.

This connects beautifully with curve sketching - you can visualise exactly how a line and parabola interact, whether they miss each other, touch once, or cross twice.

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MathsMaths192 views·Updated Jun 26, 2026·11 pages

AS Level Maths: Key Concepts in Chapters 1, 2, and 3

user profile picture
jayne@k.jayn3

Algebra and quadratics form the backbone of A-level maths, connecting everything from basic equation solving to complex real-world modelling. This comprehensive guide covers all the essential techniques you'll need to master, from completing the square to solving simultaneous equations with...

1
of 10
Algebra
and
Quadratics Rationalising Denominators

Solving Quadratic Equations

Quadratic Simultaneous Equations

Linear Simultaneous Equati

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  • Access to all documents
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Algebra and Quadratics Overview

You're about to dive into one of the most powerful areas of maths that'll serve you well beyond your A-levels. Quadratics appear everywhere - from calculating projectile paths to optimising business profits.

This topic brings together loads of interconnected skills that build on each other. Master the basics like expanding brackets and factorising, then you'll find the advanced stuff like discriminants and modelling much easier to tackle.

Key insight: Think of quadratics as a toolkit - each method (factorising, completing the square, quadratic formula) is just a different tool for the same job.

The beauty of this topic is that once you understand the patterns, you'll spot them everywhere in maths and science.

2
of 10
Algebra
and
Quadratics Rationalising Denominators

Solving Quadratic Equations

Quadratic Simultaneous Equations

Linear Simultaneous Equati

Sign up to see the content. It's free!

  • Access to all documents
  • Improve your grades
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Topic Mind Map

Your quadratic journey covers these essential skills that all connect together brilliantly. Index laws and surds give you the foundation, whilst expanding brackets and factorising are your go-to techniques for simplifying expressions.

The real power comes with solving quadratic equations using methods like completing the square and the quadratic formula. You'll also explore how the discriminant tells you exactly how many solutions to expect.

Functions and quadratic graphs help you visualise what's happening, while simultaneous equations (both linear and quadratic) show how different relationships interact. Quadratic inequalities and graphic inequalities extend this to ranges of values.

Study tip: Don't try to learn these topics in isolation - they're all connected and understanding one makes the others much clearer.

Finally, modelling with quadratics shows you how all this theory applies to real-world problems, making your maths genuinely useful.

3
of 10
Algebra
and
Quadratics Rationalising Denominators

Solving Quadratic Equations

Quadratic Simultaneous Equations

Linear Simultaneous Equati

Sign up to see the content. It's free!

  • Access to all documents
  • Improve your grades
  • Join milions of students

Completing the Square

Completing the square transforms messy quadratics into a much cleaner form that's easier to work with. Think of it as reorganising your bedroom - same stuff, but now you can actually find things!

The basic pattern is turning ax2+bx+cax^2 + bx + c into (x+b2)2+constant(x + \frac{b}{2})^2 + \text{constant}. For 2x2+6x+72x^2 + 6x + 7, you get (x+3)2+9(x + 3)^2 + 9. The key is halving the coefficient of xx, then adjusting the constant.

When the coefficient of x2x^2 isn't 1, just factor it out first. For 2x2+2x+22x^2 + 2x + 2, factor out the 2 to get 2(x2+x+1)2(x^2 + x + 1), then complete the square inside the brackets.

Exam tip: Completing the square is brilliant for finding turning points of parabolas and solving quadratics that don't factorise neatly.

This technique is your secret weapon for tricky exam questions - once you've got the completed square form, finding vertices, roots, and ranges becomes straightforward.

4
of 10
Algebra
and
Quadratics Rationalising Denominators

Solving Quadratic Equations

Quadratic Simultaneous Equations

Linear Simultaneous Equati

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  • Access to all documents
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Functions and Finding Roots

A function is just a mathematical machine that takes an input and gives you exactly one output. The notation f(x)f(x) simply means "function of xx" - nothing scary about it!

The domain is your set of possible inputs, whilst the range is all the possible outputs. Think of a vending machine: you can only put in certain coins (domain), and you only get specific snacks out (range).

Finding roots means solving f(x)=0f(x) = 0 - basically asking "when does this function hit the x-axis?". You can use completing the square or the quadratic formula for this. For f(x)=x2+6x+5f(x) = x^2 + 6x + 5, factorising gives you (x+1)(x+5)=0(x+1)(x+5) = 0, so x=1x = -1 or x=5x = -5.

Quick check: Always verify your roots by substituting back into the original equation.

Functions are everywhere in real life - from calculating your phone bill to predicting population growth. Master the basics here and you'll breeze through more advanced topics later.

5
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Algebra
and
Quadratics Rationalising Denominators

Solving Quadratic Equations

Quadratic Simultaneous Equations

Linear Simultaneous Equati

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Surds and Rationalising Denominators

Surds are just square roots that don't work out to nice whole numbers. So 9=3\sqrt{9} = 3 (not a surd), but 7\sqrt{7} stays as 7\sqrt{7} because there's no simpler form.

The key surd rules are: a×b=ab\sqrt{a} \times \sqrt{b} = \sqrt{ab} and ab=ab\frac{\sqrt{a}}{\sqrt{b}} = \sqrt{\frac{a}{b}}. To simplify surds, look for square factors: 8=4×2=22\sqrt{8} = \sqrt{4 \times 2} = 2\sqrt{2}.

Rationalising denominators means getting rid of surds from the bottom of fractions. When you've got something like 5abc\frac{5}{a\sqrt{b} - c}, multiply top and bottom by the conjugate (ab+c)(a\sqrt{b} + c) to eliminate the surd.

Memory trick: Think of rationalising as "making the denominator rational" - no square roots allowed on the bottom!

This might seem purely theoretical, but surds pop up constantly in trigonometry, calculus, and physics. Getting comfortable with them now saves you loads of time later.

6
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Algebra
and
Quadratics Rationalising Denominators

Solving Quadratic Equations

Quadratic Simultaneous Equations

Linear Simultaneous Equati

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The Quadratic Formula

The quadratic formula x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} is your reliable backup when factorising gets messy. It works for any quadratic equation in the form ax2+bx+c=0ax^2 + bx + c = 0.

For x2+5x+3=0x^2 + 5x + 3 = 0, you've got a=1a = 1, b=5b = 5, c=3c = 3. Plugging these in gives x=5±132x = \frac{-5 \pm \sqrt{13}}{2}. The ±\pm means you get two solutions (or sometimes one repeated solution).

With 3x22x4=03x^2 - 2x - 4 = 0, be careful with signs: a=3a = 3, b=2b = -2, c=4c = -4. This gives x=2±526=1±133x = \frac{2 \pm \sqrt{52}}{6} = \frac{1 \pm \sqrt{13}}{3} after simplifying.

Formula tip: Always double-check your aa, bb, and cc values - getting these wrong is the most common mistake.

The quadratic formula never lets you down, even when the numbers get ugly. It's particularly useful for non-calculator questions where exact answers with surds are expected.

7
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Algebra
and
Quadratics Rationalising Denominators

Solving Quadratic Equations

Quadratic Simultaneous Equations

Linear Simultaneous Equati

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The Discriminant

The discriminant is the bit under the square root in the quadratic formula: b24acb^2 - 4ac. It's like a crystal ball that tells you exactly how many solutions your quadratic has before you even solve it!

When b24ac>0b^2 - 4ac > 0, you get two distinct roots - your parabola crosses the x-axis twice. When b24ac=0b^2 - 4ac = 0, there's one repeated root - the parabola just touches the x-axis at one point.

If b24ac<0b^2 - 4ac < 0, you get no real roots - your parabola doesn't touch the x-axis at all. This is incredibly useful for sketching graphs and understanding the behaviour of quadratic functions.

Graph connection: The discriminant tells you about x-intercepts without having to draw the whole graph.

This concept becomes crucial when you're analysing quadratic inequalities or determining how many times a line intersects a curve. It's one of those tools that seems simple but proves incredibly powerful.

8
of 10
Algebra
and
Quadratics Rationalising Denominators

Solving Quadratic Equations

Quadratic Simultaneous Equations

Linear Simultaneous Equati

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  • Access to all documents
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Modelling With Quadratics

Real-world applications of quadratics are everywhere, and projectile motion is a classic example. The equation h(t)=12.25+14.7t4.9t2h(t) = 12.25 + 14.7t - 4.9t^2 models an object's height over time.

The constant term (12.25) represents the initial height when t=0t = 0. The coefficient of t2t^2 is negative because gravity pulls objects downward, creating the characteristic parabolic path.

To find when the object hits the ground, set h(t)=0h(t) = 0 and solve. Using completing the square or the quadratic formula, you get t=3.68t = 3.68 seconds (ignoring the negative solution since time can't be negative).

Real-world tip: Always consider whether your mathematical solutions make physical sense in the context.

Quadratic modelling appears in business (profit optimisation), engineering (structural design), and countless other fields. Understanding how to interpret the coefficients and solve these problems gives you powerful analytical skills.

9
of 10
Algebra
and
Quadratics Rationalising Denominators

Solving Quadratic Equations

Quadratic Simultaneous Equations

Linear Simultaneous Equati

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Simultaneous Equations

Simultaneous equations are like mathematical puzzles where you find values that satisfy multiple conditions at once. You might get one solution, two solutions, no solutions, or even infinite solutions depending on how the equations relate.

Elimination works by adding or subtracting equations to eliminate variables. For 3x+y=83x + y = 8 and 6x3y=96x - 3y = 9, multiply the first by 3 to get matching yy terms, then add to eliminate yy completely.

Substitution involves solving one equation for a variable, then plugging that into the other equation. It's particularly useful when you've got quadratic simultaneous equations where one equation has squared terms.

Strategy choice: Use elimination for linear systems, substitution when you've got quadratics or when one equation is already solved for a variable.

Graphically, solutions are intersection points. Linear equations give straight lines, whilst quadratic equations give curves. Where they cross represents your solution coordinates.

10
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Algebra
and
Quadratics Rationalising Denominators

Solving Quadratic Equations

Quadratic Simultaneous Equations

Linear Simultaneous Equati

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Quadratic Simultaneous Equations

When you mix quadratic and linear equations, things get more interesting - you can get up to two intersection points. Start by substituting the linear equation into the quadratic one.

For x2+y=3x^2 + y = 3 and y=x23x+1y = x^2 - 3x + 1, substitute to get x2+(x23x+1)=3x^2 + (x^2 - 3x + 1) = 3, which simplifies to x2x2=0x^2 - x - 2 = 0. Factorising gives (x+1)(x2)=0(x+1)(x-2) = 0, so x=1x = -1 or x=2x = 2.

The discriminant predicts how many solutions you'll get before solving. After substitution and simplification, calculate b24acb^2 - 4ac for your resulting quadratic. Positive means two intersections, zero means one (tangent), negative means none.

Discriminant power: Use b24acb^2 - 4ac to check your work - if you found two solutions but the discriminant is negative, you've made an error somewhere.

This connects beautifully with curve sketching - you can visualise exactly how a line and parabola interact, whether they miss each other, touch once, or cross twice.

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