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Calculus 1Calculus 1116 views·Updated May 29, 2026·1 page

Understanding Limits and Continuity: Basics Explained

user profile picture
aa@ayarn

Limits and continuity form the foundation of calculus, providing the... Show more

1
of 1
# Limits & Continuity

Theorem of composite
functions

$lim_{x \to a} f(g(x)) = f(lim_{x \to a} g(x))$ has to
be true

examples

theorems

$

Limits & Continuity: Key Concepts and Techniques

Ever wondered what happens when you approach a point on a graph but never quite reach it? That's what limits help us understand! When working with limits, we have several techniques to find their values.

Direct substitution is the simplest approach - just plug in the value. For example, limx1(6x2+5x1)=6(1)2+5(1)1=651=0\lim_{x \to -1} (6x^2 + 5x - 1) = 6(-1)^2 + 5(-1) - 1 = 6 - 5 - 1 = 0. Remember, a function is continuous at point aa if limxaf(x)=f(a)\lim_{x \to a} f(x) = f(a).

With composite functions, we can use the theorem: limxaf(g(x))=f(limxag(x))\lim_{x \to a} f(g(x)) = f(\lim_{x \to a} g(x)), but only when limxag(x)\lim_{x \to a} g(x) exists and ff is continuous at that limit. For trigonometric functions, we apply direct substitution: limxπsin(x)=sin(π)=0\lim_{x \to \pi} \sin(x) = \sin(\pi) = 0.

Piecewise functions require checking the appropriate piece based on where aa falls. For example, with f(x)={x+2for 0x4sqrtxfor x>4f(x) = \begin{cases}x + 2 & \text{for } 0 \leq x \leq 4\\sqrt{x} & \text{for } x > 4\end{cases}, you need to evaluate the limit from the left and right at transition points to determine if the overall limit exists.

Pro Tip: When facing a rational function with a zero in the denominator, try factoring first! Often, you can cancel terms to find a simplified expression valid everywhere except at that problematic point.

Sometimes limits don't exist (DNE), especially when approaching from different directions gives different results, or when we end up with indeterminate forms like 00\frac{0}{0}.

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Calculus 1Calculus 1116 views·Updated May 29, 2026·1 page

Understanding Limits and Continuity: Basics Explained

user profile picture
aa@ayarn

Limits and continuity form the foundation of calculus, providing the tools to analyze function behavior at specific points. These concepts are crucial for understanding rates of change and determining what happens as values approach certain points on a graph.

1
of 1
# Limits & Continuity

Theorem of composite
functions

$lim_{x \to a} f(g(x)) = f(lim_{x \to a} g(x))$ has to
be true

examples

theorems

$

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Limits & Continuity: Key Concepts and Techniques

Ever wondered what happens when you approach a point on a graph but never quite reach it? That's what limits help us understand! When working with limits, we have several techniques to find their values.

Direct substitution is the simplest approach - just plug in the value. For example, limx1(6x2+5x1)=6(1)2+5(1)1=651=0\lim_{x \to -1} (6x^2 + 5x - 1) = 6(-1)^2 + 5(-1) - 1 = 6 - 5 - 1 = 0. Remember, a function is continuous at point aa if limxaf(x)=f(a)\lim_{x \to a} f(x) = f(a).

With composite functions, we can use the theorem: limxaf(g(x))=f(limxag(x))\lim_{x \to a} f(g(x)) = f(\lim_{x \to a} g(x)), but only when limxag(x)\lim_{x \to a} g(x) exists and ff is continuous at that limit. For trigonometric functions, we apply direct substitution: limxπsin(x)=sin(π)=0\lim_{x \to \pi} \sin(x) = \sin(\pi) = 0.

Piecewise functions require checking the appropriate piece based on where aa falls. For example, with f(x)={x+2for 0x4sqrtxfor x>4f(x) = \begin{cases}x + 2 & \text{for } 0 \leq x \leq 4\\sqrt{x} & \text{for } x > 4\end{cases}, you need to evaluate the limit from the left and right at transition points to determine if the overall limit exists.

Pro Tip: When facing a rational function with a zero in the denominator, try factoring first! Often, you can cancel terms to find a simplified expression valid everywhere except at that problematic point.

Sometimes limits don't exist (DNE), especially when approaching from different directions gives different results, or when we end up with indeterminate forms like 00\frac{0}{0}.

We thought you’d never ask...

What is the Knowunity AI companion?

Our AI companion is specifically built for the needs of students. Based on the millions of content pieces we have on the platform we can provide truly meaningful and relevant answers to students. But its not only about answers, the companion is even more about guiding students through their daily learning challenges, with personalised study plans, quizzes or content pieces in the chat and 100% personalisation based on the students skills and developments.

Where can I download the Knowunity app?

You can download the app in the Google Play Store and in the Apple App Store.

Is Knowunity really free of charge?

That's right! Enjoy free access to study content, connect with fellow students, and get instant help – all at your fingertips.

Can't find what you're looking for? Explore other subjects.

Students love us — and so will you.

4.6/5App Store
4.7/5Google Play

The app is very easy to use and well designed. I have found everything I was looking for so far and have been able to learn a lot from the presentations! I will definitely use the app for a class assignment! And of course it also helps a lot as an inspiration.

Stefan SiOS user

This app is really great. There are so many study notes and help [...]. My problem subject is French, for example, and the app has so many options for help. Thanks to this app, I have improved my French. I would recommend it to anyone.

Samantha KlichAndroid user

Wow, I am really amazed. I just tried the app because I've seen it advertised many times and was absolutely stunned. This app is THE HELP you want for school and above all, it offers so many things, such as workouts and fact sheets, which have been VERY helpful to me personally.

AnnaiOS user